Calculator
Example data
| Scenario | Inputs | Expected PF | Notes |
|---|---|---|---|
| Workshop motor | P=12 kW, S=15 kVA, Lagging | 0.80 | Q ≈ 9 kVAr |
| HVAC unit | P=8 kW, Q=6 kVAr, Lagging | 0.80 | S=10 kVA |
| 3φ pump | V=400 V, I=25 A, P=13 kW | ≈0.75 | Uses √3·V·I |
Formula used
- Power factor: PF = P / S
- Apparent power: S = √(P² + Q²)
- Reactive power (magnitude): |Q| = √(S² − P²)
- Phase angle: φ = arccos(|PF|) (in degrees)
- From voltage and current:
- Single-phase: S(kVA)= V·I / 1000
- Three-phase: S(kVA)= √3·Vline·I / 1000
- Correction kVAr (lagging loads): Qc = P·(tanφ₁ − tanφ₂)
- Capacitance estimate:
- Single-phase: C = (Qc·1000)/(2πf·V²)
- Three-phase delta: C = (Qc·1000)/(3·2πf·VLL²)
- Three-phase star: uses Vph=VLL/√3 per phase.
Sign convention: lagging Q is positive, leading Q is negative.
How to use this calculator
- Select a method that matches your available measurements.
- Choose single-phase or three-phase, then pick load type.
- Enter the required values, then press Submit.
- Review PF, φ, P, Q, and S in the Results panel.
- Optionally set a target PF to estimate correction kVAr and µF.
- Use the download buttons to export CSV or PDF files.
FAQs
1) What does power factor indicate?
It shows how effectively electrical power becomes useful work. A lower PF means more current for the same kW, increasing losses and voltage drop.
2) Why is lagging power factor common?
Most motors and transformers are inductive, so current lags voltage. This produces positive reactive power and reduces PF compared with purely resistive loads.
3) Can power factor be greater than 1?
No. PF magnitude is between 0 and 1. If you see a value above 1, recheck units, phase selection, and whether P, Q, or S were entered correctly.
4) What is the difference between kW, kVA, and kVAr?
kW is real power used for work. kVAr is reactive power that oscillates in fields. kVA is apparent power, combining both as the total demand on the supply.
5) How does three-phase affect calculations?
For V–I based apparent power, three-phase uses √3·Vline·I. Enter line-to-line voltage and RMS current to estimate kVA and PF properly.
6) When should I use the correction estimate?
Use it when your load is inductive and you want a higher PF, such as 0.95. It estimates the capacitor kVAr needed to reduce reactive power.
7) Is the capacitance value exact for real installations?
It is an estimate. Real systems consider harmonics, temperature, capacitor tolerances, and switching steps. Confirm with equipment datasheets and qualified engineering review.