| System (V) | Load | Length | Cable | Vdrop (V) | Drop (%) |
|---|---|---|---|---|---|
| 400 | 100 A, PF 0.85 lag | 120 m | Copper 35 mm², X=0.08 Ω/km | 10.13 | 2.53 |
| 480 | 60 kW, PF 0.90 lag, η 0.95 | 250 m | Aluminum 70 mm² @60°C, X=0.09 Ω/km | 16.85 | 3.51 |
| 11000 | 150 A, PF 0.80 lag | 2 km | Overhead planning, R=0.20 Ω/km, X=0.35 Ω/km | 192.26 | 1.75 |
| 400 | 80 A, PF 0.90 lead | 100 m | Copper 50 mm² @40°C, X=0.08 Ω/km | 4.15 | 1.04 |
- Enter your system line-to-line voltage and the run length.
- Select a load mode: current (A) or power (kW) with efficiency.
- Set power factor and choose lagging or leading behavior.
- Choose size-based estimate or enter custom R/X from your datasheet.
- Set parallel runs if multiple conductors share each phase.
- Press Submit to see voltage drop, percent drop, losses, and maximum length.
- Use Download CSV or PDF to save the calculation record.
Voltage drop targets in practice
Many facilities set a feeder drop target near 3% and a combined feeder-plus-branch target near 5%. At 400 V, a 3% limit equals 12 V. The calculator reports both volts and percent, so you can compare directly with project specifications and commissioning checks.
Current, power factor, and efficiency
When you enter kW, the tool converts to current using I = P /(√3·VLL·PF·η). For example, 60 kW at 480 V, PF 0.90, and η 0.95 produces about 84.2 A. A lower power factor increases current and raises both voltage drop and I²R losses.
Resistance, temperature, and material choice
Conductor resistance changes with operating temperature. Using copper at 40°C instead of 20°C increases resistance by roughly 7.9% with α≈0.00393/°C. Aluminum uses a higher resistivity and a slightly different temperature coefficient, so equal-area aluminum typically yields higher drop unless the size is increased.
Reactance assumptions and leading power factor
For planning, typical cable reactance ranges around 0.08–0.09 Ω/km for close-spaced cables, while overhead lines can be far higher depending on spacing. The drop term uses R·cosφ ± X·sinφ. With leading PF, the reactive term can reduce the net drop, and in rare cases the receiving voltage can rise slightly.
Parallel runs and scaling behavior
Parallel conductors divide both R and X by the number of runs, assuming equal sharing. Two identical runs halve impedance, cutting voltage drop roughly in half at the same current. Losses also drop because Ploss = 3·I²·R, and R falls with each added parallel path. If losses are 2 kW during 3,000 hours annually, wasted energy is 6,000 kWh, significantly impacting operating cost.
Using results for sizing decisions
The maximum-length output estimates how far you can run before reaching the allowable percent drop at the entered load. If your actual length exceeds that value, increase conductor size, add parallel runs, improve power factor, or raise system voltage. Always validate with manufacturer impedance data for final design.