Calculator
Example data
| Source | Temperature (K) | Peak wavelength (approx.) | Region |
|---|---|---|---|
| Sun (photosphere) | 5778 | ~502 nm | Visible (green) |
| Tungsten filament | 3000 | ~966 nm | Near‑infrared |
| Room temperature | 295 | ~9.82 µm | Mid‑infrared |
| Molten lava | 1200 | ~2.41 µm | Infrared |
These values use Wien’s displacement peak per wavelength (Bλ).
Formula used
The wavelength peak of a black body spectrum (per wavelength) is estimated using Wien’s displacement law:
λpeak = b / T
- λpeak is the peak wavelength (meters).
- b is Wien’s displacement constant (m·K).
- T is absolute temperature (Kelvin).
If you select the frequency peak (Bν), the calculator also computes: νpeak = x·k·T / h and reports the equivalent wavelength λ = c/ν.
How to use this calculator
- Enter the temperature of the emitter.
- Select the temperature unit you have.
- Choose whether you want the wavelength peak (Bλ) or the frequency peak (Bν).
- Optionally adjust decimals or switch to scientific notation.
- Press Calculate to see results above the form.
- Use the download buttons to save CSV or PDF outputs.
Black body peak wavelength guide
1) Why the peak wavelength shifts
Hotter objects radiate more strongly at shorter wavelengths. Using Wien’s law, doubling absolute temperature halves the peak wavelength. For example, 3000 K peaks near 966 nm, while 6000 K peaks near 483 nm. This helps connect “color temperature” with real spectral behavior.
2) Typical temperature bands and regions
Around 200–350 K, most peaks fall in the mid‑infrared (roughly 8–15 µm). Incandescent filaments near 2500–3200 K peak in the near‑infrared (0.9–1.2 µm). Stellar photospheres around 5000–7000 K peak in the visible band (about 400–600 nm), which matches everyday sunlight perception.
3) Unit handling that prevents mistakes
The calculator converts Celsius and Fahrenheit to Kelvin before computation. A small unit slip can be huge: using 3000 as °C instead of K changes the Kelvin value to 3273.15 K, shifting the peak from 966 nm to about 885 nm. Always verify the displayed Kelvin value in the result panel.
4) Peak per wavelength vs peak per frequency
“Peak wavelength” depends on how the spectrum is plotted. The peak of Bλ occurs at λpeak=b/T. The peak of Bν occurs at νpeak≈2.82144·kT/h. These are both correct, but they point to different wavelengths when converted, so use the mode that matches your data source.
5) Constant selection and precision
The default Wien constant is close to 2.897771955×10⁻³ m·K. If your reference uses a rounded constant (for example 2.90×10⁻³), the relative difference is small, typically under 0.1%. The decimals and scientific notation options help you match lab reporting formats without manual rounding.
6) Practical uses in measurement
Infrared sensors are usually sensitive over a band, not a single wavelength. Still, the peak wavelength is a strong first estimate for choosing filters, detectors, or camera ranges. For room‑temperature targets near 10 µm, long‑wave infrared systems (8–14 µm) are often appropriate.
7) Documenting results for projects
After calculating, export CSV for spreadsheets or PDF for reports. Include the input temperature, the Kelvin conversion, the peak definition you selected, and the constant used. This makes your calculations reproducible when comparing experiments, simulations, or instrument specifications.
FAQs
1) What does “peak wavelength” mean here?
It is the wavelength where spectral radiance per wavelength, Bλ, reaches its maximum for an ideal emitter. It is computed with Wien’s displacement law using temperature in Kelvin.
2) Why does the frequency peak give another wavelength?
The spectrum shape changes with the variable used. The maximum of Bν occurs at a different point than the maximum of Bλ, so converting νpeak to λ does not match λpeak.
3) Can I use Celsius or Fahrenheit safely?
Yes. Enter the temperature and select the correct unit. The calculator converts to Kelvin internally and shows the Kelvin value in results so you can confirm the conversion.
4) What value of the Wien constant should I use?
Use the default unless your textbook or standard specifies a different rounded value. A slightly different constant changes the result proportionally, usually by a very small percentage.
5) Does emissivity affect the peak wavelength?
Emissivity mainly scales intensity and can vary with wavelength, but for many practical cases the peak location is still approximated well using Wien’s law. Strong wavelength‑dependent emissivity can shift the apparent peak.
6) Why is my output outside the visible range?
Many real objects are cooler than the Sun. At 300 K, the peak is near 10 µm in the infrared, so you cannot “see” the peak with your eyes even though the object emits radiation.