Estimate electric power from key circuit measurements quickly. Choose DC, single‑phase, or three‑phase methods easily. See energy, cost, and losses for smarter decisions today.
Use RMS values for AC. For three‑phase, assume a balanced load.
| Scenario | Inputs | Calculated Power | Notes |
|---|---|---|---|
| DC device | V = 12 V, I = 2 A | 24 W | Battery powered electronics |
| Resistive heater | V = 230 V, R = 46 Ω | 1150 W | Uses P = V² ÷ R |
| AC motor load | V = 230 V, I = 5 A, PF = 0.85 | 977.5 W | Real power differs from VA |
| Three‑phase system | VL = 400 V, IL = 10 A, PF = 0.9 | 6235.4 W | Balanced approximation |
Electric power is the rate at which electrical energy is converted into another form, such as heat, light, or mechanical work. It is measured in watts, where 1 W equals 1 joule per second. In practical systems, power levels often scale to kilowatts for appliances and megawatts for industrial loads and generation.
For direct current systems, power is commonly computed using P = V × I when voltage and current are known. When resistance is available, Ohm’s law enables alternative forms: P = I²R and P = V²/R. These relationships are fundamental for sizing resistors, estimating heating, and checking battery runtime assumptions.
In alternating current circuits, the voltage and current can be out of phase due to inductance and capacitance. Apparent power S is measured in volt‑amperes (VA) and equals Vrms × Irms. Real power P equals S × PF, where power factor (PF) ranges from 0 to 1 and represents how effectively current produces useful work.
Reactive power Q, measured in var, captures energy that oscillates between the source and reactive components. It can be estimated from Q = S × sin(φ), with PF = cos(φ). A lower PF increases current for the same real power, which can raise conductor losses and reduce system capacity. This calculator reports Q and phase angle to support diagnostics.
Many motors and industrial feeders use balanced three‑phase power. For these systems, apparent power is S = √3 × VL × IL. Real power then follows P = S × PF. Because three‑phase delivers smoother torque and improved efficiency for large machines, accurate power estimates help with breaker sizing and transformer selection.
Power becomes energy when multiplied by time. The calculator converts operating time to hours and computes energy in watt‑hours and kilowatt‑hours. For example, a 1.15 kW heater running 3 hours consumes 3.45 kWh. Energy totals are the basis for monthly consumption planning and generator or UPS capacity comparisons.
Electricity bills are typically based on kWh. By entering a rate per kWh, the tool estimates cost using Cost = kWh × rate. This is useful for comparing operating scenarios, such as running a pump at different duty cycles or evaluating how improved power factor can reduce demand‑related impacts in some tariffs.
Real systems rarely convert all input power to useful output. If efficiency is provided, the calculator estimates output power and losses. Alternatively, if you set a desired output power and efficiency, it computes required input power. This supports motor selection, power supply headroom checks, and thermal management planning under realistic conditions.
Watts represent real power that performs work. Volt‑amperes represent apparent power, based on RMS voltage and current. In AC circuits, VA can be higher than W when power factor is below 1.
Use P = I²R when you know current and resistance directly, such as with a resistor network. Use P = V × I when you measure voltage and current at the same point in the circuit.
For a fixed real power, lower power factor means more apparent power is required. Since apparent power equals V × I, the current must rise, which increases I²R losses and voltage drop.
Use RMS voltage for AC. Household mains values like 120 V or 230 V are RMS. For three‑phase, enter line‑to‑line RMS voltage when using the three‑phase mode.
It computes apparent power S and uses the phase angle derived from PF = cos(φ). Reactive power is then Q = S × sin(φ). This assumes sinusoidal steady‑state conditions.
Yes. Enter operating time and a rate per kWh. The tool calculates kWh and multiplies by the rate to estimate cost for that run time, which you can scale to weeks or months.
Enter desired output power and efficiency. The calculator computes the required input power as output divided by efficiency. This helps choose a power supply or driver with adequate headroom.
Important Note: All the Calculators listed in this site are for educational purpose only and we do not guarentee the accuracy of results. Please do consult with other sources as well.