Store more insight by checking energy in capacitors. Switch modes, convert units, and validate results. Download CSV or PDF, then share calculations with confidence.
| Mode | Capacitance | Voltage | Charge | Energy (J) |
|---|---|---|---|---|
| C and V | 10 uF | 12 V | 120 uC | 0.00072 |
| Q and V | 100 uF | 5 V | 500 uC | 0.00125 |
| Geometry and V | ~2.656e-10 F | 100 V | ~2.656e-08 C | ~1.328e-06 |
The stored energy in an ideal capacitor equals the work required to move charge onto its plates. Depending on which quantities you know, use any equivalent expression below.
For a simple parallel-plate model, capacitance is: C = ε₀ εᵣ A / d, where ε₀ is vacuum permittivity, εᵣ is relative permittivity, A is plate area, and d is separation.
A capacitor stores energy in an electric field between conductors. When voltage rises from 0 to V, the field strengthens and work is done to move charge onto the plates. This calculator reports that work as energy in joules, plus quick conversions to watt-hours and smaller scales.
For an ideal capacitor, energy depends on capacitance and voltage as E = ½ C V². Because energy scales with V², doubling voltage quadruples stored energy. This is why voltage ratings matter as much as capacitance when comparing designs.
If you know charge, you can compute energy with E = ½ Q V, or E = Q²/(2C). The calculator derives the missing variable (Q = C V or V = Q/C) so the final energy is consistent across modes.
Capacitors often use microfarads or nanofarads, while charges are commonly microcoulombs. Small values can still produce meaningful energy for pulse loads. Use the displayed mJ, µJ, and nJ conversions to sanity-check whether a result is reasonable for your component size.
When capacitance is not directly known, the geometry mode estimates it using C = ε₀ εᵣ A / d. Increasing plate area increases capacitance linearly, while increasing separation reduces capacitance. The dielectric constant εᵣ can multiply capacitance several times compared to air.
Stored energy is not the same as deliverable energy in all circuits. Internal resistance, leakage, and switching losses reduce what reaches the load. Always stay within the voltage rating and consider surge conditions, because energy rises rapidly with voltage.
Engineers use capacitor energy for camera flashes, hold-up time in power supplies, snubber networks, pulse forming, and defibrillator-style energy estimates at a conceptual level. Comparing multiple capacitors in joules helps you pick a part that matches required pulse energy.
The result panel shows capacitance, voltage, charge, and energy in SI units for clarity. Export CSV to archive runs, or generate a PDF summary to share calculations. If you switch input modes and get the same energy, your inputs are internally consistent.
1) Which formula should I use?
Use the mode that matches your known values. All three energy expressions are equivalent when inputs are consistent,
so switching modes is a good verification step.
2) Why does energy increase so fast with voltage?
Energy follows E = ½ C V², so it grows with the square of voltage. A small increase
in voltage can significantly raise stored energy.
3) What if I only know capacitance from geometry?
Choose the geometry mode, enter area, separation, and relative permittivity, then add voltage. The calculator
estimates capacitance using the parallel-plate model and computes energy.
4) Can energy be negative?
The stored energy magnitude is non‑negative. If you enter a negative voltage or charge, the calculator still reports
positive energy because energy depends on squared or paired terms.
5) How accurate is the geometry model?
It is idealized. Edge fringing, multilayer dielectrics, and real electrode shapes can change capacitance. Use it for
estimates or learning, and prefer measured capacitance for precision work.
6) What does watt-hour mean here?
Watt-hour is an energy unit: 1 Wh = 3600 J. The calculator converts joules to Wh to
compare capacitor energy with battery-like energy quantities.
7) Does a higher capacitance always mean higher energy?
At the same voltage, yes, because energy is proportional to capacitance. But practical limits include voltage rating,
size, internal resistance, and leakage, which affect usable performance.
Important Note: All the Calculators listed in this site are for educational purpose only and we do not guarentee the accuracy of results. Please do consult with other sources as well.