Explore ductile fracture sensitivity using stress triaxiality. Switch between principal and tensor inputs quickly today. Clean outputs guide design decisions in complex loading cases.
Stress triaxiality is defined as the ratio of mean (hydrostatic) stress to von Mises equivalent stress:
η = σm / σeq
Mean stress (tension positive):
σm = (σ1 + σ2 + σ3) / 3
Von Mises stress from principal stresses:
σeq = sqrt( ((σ1−σ2)² + (σ2−σ3)² + (σ3−σ1)²) / 2 )
In tensor mode, the calculator first finds the principal stresses from the symmetric 3×3 stress tensor and then applies the same equations.
| σ1 (MPa) | σ2 (MPa) | σ3 (MPa) | Mean σm (MPa) | Von Mises σeq (MPa) | Triaxiality η |
|---|---|---|---|---|---|
| 300 | 150 | 50 | 166.666667 | 217.944947 | 0.764719 |
| 200 | 0 | 0 | 66.666667 | 200.000000 | 0.333333 |
| 150 | 75 | 75 | 100.000000 | 75.000000 | 1.333333 |
| 300 | 0 | -300 | 0.000000 | 519.615242 | 0.000000 |
| 100 | 100 | 100 | 100.000000 | 0.000000 | Undefined |
Stress triaxiality (η) tells you how hydrostatic stress compares with shear intensity. In ductile metals, higher positive η usually promotes void growth and earlier fracture, while low η is more shear dominated. Because η is dimensionless, it is easy to compare across tests and simulations.
The mean stress σm is the “pressure-like” part of the state, while von Mises stress σeq measures distortional loading. Pure shear gives σm ≈ 0 and η near zero. A purely hydrostatic state makes σeq = 0, so η is undefined.
Uniaxial tension commonly produces η ≈ 1/3. Plane strain tension often increases η toward about 2/3, and sharp notches can push η above 1. Compression can yield negative η when σm becomes compressive. These benchmarks help validate inputs quickly.
Many ductile damage models use η to scale strain-to-failure or to evolve porosity. Higher η tends to accelerate void growth, while low η supports shear localization. Reporting η together with σeq improves calibration because it separates hydrostatic effects from overall stress magnitude.
Finite element outputs often provide σx, σy, σz and shear stresses. In tensor mode, this tool computes principal stresses from the symmetric 3×3 tensor and then evaluates η from those principals. Check that your shear terms match the symmetry assumption and your sign convention is consistent.
Two states can share the same η but have different deviatoric stress shapes, which can change fracture behavior. The Lode angle and normalized Lode parameter incorporate the third invariant (via J2 and J3). They help distinguish axisymmetric tension from shear-like states at similar η.
Units only scale σm, σeq, and the invariants; η stays unitless. Near-hydrostatic conditions can make σeq very small, so η may fluctuate. Treat η as qualitative when σeq approaches zero, and verify principal stress ordering when results look odd.
Use CSV or PDF exports to capture σm, σeq, η, J2, J3, and Lode metrics in one place. σeq should be nonnegative. If you add tensile hydrostatic stress while keeping shear similar, η should increase. Re-check tensor symmetry if checks fail.
It compares hydrostatic stress to shear-driven deformation. Higher positive values indicate more tensile “pressure,” which often increases void growth and fracture risk in ductile materials.
If von Mises stress is zero, the state is purely hydrostatic. Dividing by zero makes η undefined, so the tool flags that condition instead of returning a misleading number.
Yes. If the mean stress is compressive while shear exists, σm becomes negative and η follows. Negative η often indicates suppression of void growth under compression.
Use principal stresses from your analysis. If you only have tensor components, switch to tensor mode and the calculator will compute principal stresses internally.
η near zero suggests shear-dominated loading. This is common in torsion, simple shear, and some mixed-mode cases where hydrostatic stress is small compared with deviatoric stress.
Lode metrics capture third-invariant effects. They help distinguish different deviatoric stress shapes that can produce different ductile fracture behavior even when η is similar.
Try a simple uniaxial tension case: σ1 = S, σ2 = 0, σ3 = 0. You should get η close to 1/3 and σeq close to S.
Important Note: All the Calculators listed in this site are for educational purpose only and we do not guarentee the accuracy of results. Please do consult with other sources as well.