Compute wave number from wavelength, speed, frequency, or energy. See angular, spectroscopic, and derived wave values with helpful explanations.
| Case | Input | Wavelength | Angular Wave Number | Spectroscopic Wave Number |
|---|---|---|---|---|
| Visible Light | 500 nm | 5.0000e-7 m | 1.2566e7 rad/m | 20000.00000000 cm-1 |
| Microwave | 10 GHz, 3.0e8 m/s | 3.0000e-2 m | 209.43951024 rad/m | 0.33333333 cm-1 |
| X-ray Photon | 8 keV | 1.5498e-10 m | 4.0546e10 rad/m | 64522847.82452948 cm-1 |
Angular wave number: k = 2π / λ
Spectroscopic wave number: ṽ = 1 / λ
Wave relation: v = fλ
Frequency from period: f = 1 / T
Photon energy: E = hf
Angular frequency: ω = 2πf
Here, λ is wavelength, f is frequency, v is wave speed, T is period, E is photon energy, and h is Planck’s constant.
Wave number describes how rapidly a wave repeats in space. It is commonly reported as angular wave number in radians per meter or spectroscopic wave number in inverse centimeters.
Physics and spectroscopy often use different conventions. Angular wave number uses 2π divided by wavelength, while spectroscopic wave number uses only the reciprocal wavelength.
Use refractive index when the wave moves through a material instead of vacuum. It changes wave speed and medium wavelength while frequency stays unchanged.
Yes. If you know frequency and wave speed, wavelength equals speed divided by frequency. Then the calculator derives both angular and spectroscopic wave number values.
In spectroscopy, inverse centimeters are the standard reporting unit. This calculator also computes the reciprocal wavelength in per meter for broader physics applications.
Yes. Photon energy gives frequency through Planck’s equation. From frequency, wavelength is found, and then both wave number conventions are calculated automatically.
Nanometers are common for visible and ultraviolet light, micrometers for infrared, and meters for general wave physics. Select the unit matching your source data.
Angular wave number includes the factor 2π, converting cycles into radians. Because of that extra multiplier, its numerical value is always larger for the same wavelength.