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Enter integer coefficients for the trinomial ax² + bx + c. Results appear above this form after submission.
| Expression | a × c | Split numbers | Factor form |
|---|---|---|---|
| 2x² + 7x + 3 | 6 | 6 and 1 | (2x + 1)(x + 3) |
| 3x² - x - 2 | -6 | 2 and -3 | (3x + 2)(x - 1) |
| x² + 10x + 25 | 25 | 5 and 5 | (x + 5)(x + 5) |
For a quadratic trinomial ax² + bx + c, decomposition looks for two integers m and n such that:
After finding the pair, rewrite the middle term and factor by grouping:
ax² + bx + c = ax² + mx + nx + c
= (ax² + mx) + (nx + c)
= common factor from each group
= final product of two linear factors
The calculator also uses the discriminant b² - 4ac to report roots and graph behavior.
It means splitting the middle term of a quadratic into two parts. Those parts must add to b and multiply to a×c. Then you factor by grouping.
No. This version is designed for whole-number coefficients because standard decomposition in school algebra usually uses integer pairs and integer grouping steps.
Then the trinomial is not factorable by integer decomposition. The calculator still reports the discriminant, roots when real, and a graph of the parabola.
Factoring out the greatest common factor simplifies the trinomial. That makes the decomposition step cleaner and produces a more complete final factorization.
Yes. If the trinomial is a perfect square, the decomposition pair leads to identical linear factors, such as (x + 5)(x + 5).
Roots show where the parabola crosses the x-axis. They help verify the factors because each linear factor becomes zero at one root.
The graph shows the parabola, vertex, and real x-intercepts when they exist. It helps you connect symbolic factoring with the shape of the function.
Yes. The CSV is useful for tabular records, and the PDF works well for study notes, homework review, or printed examples.
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