Diesel Efficiency Calculator

Compare compression and cutoff effects on efficiency safely. Get percentages plus temperature ratios instantly here. Download tables, share outputs, and validate assumptions with ease.

Inputs
Enter typical ratios for an ideal Diesel cycle model.
Tip: start with gamma=1.40, r=18, rho=2.
Typical air standard: 1.35-1.40.
Often 14-22 for diesel engines.
Commonly 1.5-2.5 in idealized studies.
Reset
CSV download requires a calculation first. PDF uses your browser's print-to-PDF.
Formula used

The ideal Diesel cycle thermal efficiency depends on compression ratio r, cutoff ratio rho, and heat capacity ratio gamma.

Thermal efficiency
eta = 1 - (1 / rgamma-1) * ( (rhogamma - 1) / (gamma(rho - 1)) )

Useful ideal temperature ratios shown in results: T2/T1 = rgamma-1, T3/T2 = rho, and T4/T1 = rhogamma.

Notes: This is an air-standard model. Real engines deviate due to losses, variable gamma, finite combustion, heat transfer, pumping work, and friction.
How to use this calculator
  1. Enter gamma based on your working gas assumptions.
  2. Enter r as the maximum-to-minimum cylinder volume ratio.
  3. Enter rho as the volume ratio during constant-pressure heat addition.
  4. Click Calculate to view efficiency and diagnostic ratios.
  5. Use Download CSV for spreadsheets, or Download PDF for a report.
Example data table
gamma r rho eta (%) T2/T1 T4/T1
1.40 18.0 2.00 63.20 3.177 2.638
1.38 16.0 1.80 60.08 2.850 2.252
1.35 20.0 2.20 64.58 3.314 2.917
Values are from the ideal relations used in this calculator.
Professional notes on diesel cycle efficiency
This section supports the calculator outputs and typical engineering use.

1) What the calculator measures

This tool computes the ideal thermal efficiency of the Diesel cycle using air‑standard assumptions. It reports how effectively the cycle converts added heat into net work, based only on the compression ratio, cutoff ratio, and heat capacity ratio. Results are best for comparisons and sensitivity studies.

2) Compression ratio impact

Increasing the compression ratio raises the isentropic temperature rise during 1–2 compression, which generally improves efficiency. In the ideal model, this influence appears through rgamma−1. Practical designs balance efficiency gains against peak pressure, mechanical stress, and knock limits.

3) Cutoff ratio tradeoff

The cutoff ratio represents how long heat is added at nearly constant pressure during 2–3. Higher cutoff ratio increases expansion potential but also increases the fraction of heat rejected, so efficiency typically falls as cutoff ratio grows, holding r and gamma constant.

4) Role of the heat capacity ratio

The heat capacity ratio (gamma) links pressure, volume, and temperature changes during isentropic steps. Higher gamma tends to increase temperature sensitivity and can improve ideal efficiency for a fixed geometry. In real engines, gamma varies with temperature and mixture, so treat it as an effective average.

5) Using temperature ratios for sanity checks

The displayed ratios T2/T1, T3/T2, and T4/T1 help validate your assumptions. For example, T2/T1 should increase with compression ratio, while T4/T1 depends primarily on cutoff ratio and gamma. If values seem inconsistent, recheck unitless ratios and bounds.

6) From ideal cycle to real engine expectations

Ideal efficiency is an upper bound. Real brake thermal efficiency is reduced by heat transfer, incomplete combustion, pumping work, friction, and finite‑time mixing. Modern engines can achieve high efficiency, but always expect a gap between air‑standard predictions and measured performance.

7) Typical parameter ranges and informed inputs

For quick studies, gamma between 1.35 and 1.40 is common. Compression ratio often lies between 14 and 22, and cutoff ratio frequently ranges from about 1.5 to 2.5 in simplified analyses. Use consistent assumptions across cases to compare changes fairly.

8) Interpreting results for design decisions

Use the percentage efficiency to compare configurations, then review q_out/q_in to understand what drives change. A lower heat‑rejection fraction indicates improved conversion of supplied heat into work. Export CSV for reports and keep notes on chosen r, rho, and gamma values.

FAQs

1) Is this the same as engine fuel economy?

No. It is ideal cycle thermal efficiency, not vehicle fuel economy. Real fuel use depends on friction, pumping losses, transient operation, drivetrain losses, and operating point on the engine map.

2) What does cutoff ratio represent physically?

Cutoff ratio is the volume increase during heat addition at roughly constant pressure. It approximates the effective duration of combustion while the piston moves, affecting expansion and heat rejection.

3) Why must gamma be greater than 1?

Gamma is cp/cv for a gas. For stable gases, cp exceeds cv, so gamma is greater than 1. Values near 1 would imply unrealistic thermodynamic behavior for this model.

4) Why can the ideal efficiency look very high?

The air‑standard model neglects many real losses and assumes reversible compression and expansion. It estimates an upper bound for the cycle, so measured brake thermal efficiency is lower.

5) Which input changes efficiency the most?

Often the compression ratio has the strongest positive effect, while higher cutoff ratio tends to reduce efficiency. The exact sensitivity depends on your chosen gamma and the baseline operating point.

6) Can I use this for Otto or dual cycles?

This calculator is specific to the Diesel cycle efficiency relation. Otto and dual cycles use different heat‑addition assumptions and different closed‑form expressions, so do not mix formulas.

7) How should I create a PDF from this page?

Use the Download PDF button, which opens the browser print dialog. Select “Save as PDF” to export the current results and sections in a clean report style.

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Important Note: All the Calculators listed in this site are for educational purpose only and we do not guarentee the accuracy of results. Please do consult with other sources as well.