Calculator
Example Data Table
| Device | Power | Ambient | Max Device | Airflow | Typical h | Design Note |
|---|---|---|---|---|---|---|
| LED driver transistor | 18 W | 30 °C | 90 °C | Natural | 8 W/m²K | Needs large surface area. |
| Power amplifier module | 45 W | 25 °C | 85 °C | Light fan | 25 W/m²K | Fan reduces area. |
| Motor controller MOSFETs | 80 W | 40 °C | 100 °C | Forced duct | 60 W/m²K | Check interface resistance. |
| Voltage regulator | 12 W | 35 °C | 105 °C | Natural | 10 W/m²K | Radiation may help. |
Formula Used
Design heat load: Pdesign = P × safety factor
Thermal resistance budget: RθSA = (Tmax - Tambient) / Pdesign - RθJC - RθCS
Safe sink temperature: Tsink = Tmax - Pdesign × (RθJC + RθCS)
Surface heat flux: q/A = h(Tsink - Tambient) + εσ(Tsink,K4 - Tambient,K4)
Required area: A = Pdesign / [ηfin × Fuse × q/A]
Auto fin efficiency: ηfin = tanh(mL) / mL, where m = √(2h / kt)
How to Use This Calculator
- Enter the heat that the device must dissipate in watts.
- Enter ambient air temperature and maximum device temperature.
- Add junction to case and case to sink thermal resistance.
- Choose a safety factor for load changes and aging.
- Enter a convection coefficient based on airflow conditions.
- Set emissivity for the heat sink surface finish.
- Use auto fin efficiency or enter a known value.
- Press calculate, then download CSV or PDF if needed.
Heat Sink Area Planning
A heat sink does one simple job. It moves heat away from a part. The hard part is sizing it before the part overheats. This calculator starts with power loss, ambient temperature, and the maximum allowed part temperature. It then subtracts the internal thermal drops through the package and interface. The remaining temperature rise belongs to the heat sink.
Why Area Matters
Surface area controls how much heat can move into air. A larger area lowers heat flux. Lower heat flux usually means a lower sink temperature. Fins help because they add area without using a huge base plate. Yet fins are not perfect. Long thin fins may stay cooler near the tip. That is why fin efficiency is included. Forced air also changes the answer. A fan can raise the convection coefficient many times above still air.
Thermal Resistance View
Engineers often use thermal resistance for early design. The total resistance equals temperature rise divided by heat. Package resistance, interface resistance, and sink resistance are in series. The calculator finds the allowed sink to ambient resistance. A negative value means the chosen temperature limit is too strict. It may also mean the device power is too high.
Convection and Radiation View
Area is estimated from convection and optional radiation. Convection uses the heat transfer coefficient, area, and temperature difference. Radiation uses emissivity and absolute temperatures. Black anodized surfaces usually radiate better than shiny metal. Radiation may help in natural convection. It is often less important when strong airflow is present.
Practical Design Notes
Use realistic input values. Do not choose a very high air coefficient unless the fan path is controlled. Keep dust, blocked vents, altitude, and enclosure heating in mind. Add a safety factor for aging and uncertain load. Check the result against real heat sink data when possible. Manufacturer curves are still important. They include fin spacing, base spreading, airflow direction, and mounting details. This calculator gives a strong first estimate. Testing should confirm the final design.
Reading the Output
The required area is shown in several units. The equivalent square side is only a guide. Real heat sinks use fins, gaps, and bases. Compare the effective area with catalog surface area values.
FAQs
1. What does heat sink area mean?
It means the effective surface area that transfers heat to air. It includes fins, exposed base surfaces, and other cooling surfaces that actually receive airflow.
2. Why is thermal resistance important?
Thermal resistance links heat flow to temperature rise. A lower value means heat moves more easily from the device to ambient air.
3. What is a good convection coefficient?
Still air often uses 5 to 15 W/m²K. Light forced air may use 25 W/m²K or more. Strong ducted airflow can be much higher.
4. Should I include radiation?
Include radiation for hot surfaces, natural convection, and dark finishes. It is usually less dominant when forced airflow is strong.
5. What is fin efficiency?
Fin efficiency shows how well a fin uses its area. Thin, long fins may not stay equally hot from base to tip.
6. Why use a safety factor?
A safety factor covers load variation, dust, aging fans, high ambient days, and uncertain thermal data. It makes the estimate more conservative.
7. Can this replace manufacturer heat sink charts?
No. It gives an early estimate. Final selection should compare the result with manufacturer thermal resistance curves and real testing.
8. Why is my required area very large?
The temperature rise may be small, airflow may be weak, or heat load may be high. Improve airflow or allow a higher safe sink temperature.