Helmholtz Free Energy Calculator

Plan spontaneous change with a quick free energy estimate. Choose which variable to solve quickly. Get clean results, conversions, and exports in one place.

Inputs
Pick what you want to solve, then enter the required values.
Core relation: A = U − T·S
Required when solving for A, T, or S.
Required when solving for U, T, or S.
Must be greater than 0 K in base units.
Use positive values for most macroscopic systems.
Used for A or U outputs.
Used only when solving for temperature.
Used only when solving for entropy.
Reset
Tip: If you solve for T or S, avoid zeros in the denominator.

Formula Used

Helmholtz free energy (often written as A or F) is defined as: A = U − T·S

  • U is internal energy (J).
  • T is absolute temperature (K).
  • S is entropy (J/K).

Under constant temperature and volume, systems tend to move toward lower Helmholtz free energy.

How to Use This Calculator

  1. Select what you want to solve for (A, U, T, or S).
  2. Enter the required inputs and choose their units.
  3. Pick output units for energy, temperature, or entropy as needed.
  4. Click Calculate to see results above the form.
  5. Use the CSV or PDF buttons to export the computed summary.

Example Data Table

Case Internal Energy U (J) Temperature T (K) Entropy S (J/K) Helmholtz A = U − T·S (J)
1 5000 300 10 2000
2 12000 350 18 5700
3 8000 298 12.5 4275

These values are illustrative and depend on your chosen reference state.

Helmholtz Free Energy Guide

1) What this calculator measures

Helmholtz free energy, A, measures the “useful” energy available to do work when a system is held at constant temperature and constant volume. It is central in thermal physics, statistical mechanics, and materials work. Lower values indicate a more favorable equilibrium state for the same T and V.

2) Variables and typical data ranges

The calculator uses A = U − T·S. Internal energy U is commonly reported in joules, kilojoules, or electronvolts. Temperature T must be absolute; room conditions are about 298 K. Entropy S is often in J/K; for many macroscopic samples, values from 1 to 10,000 J/K are possible depending on size and units basis.

3) Why constant temperature and volume matters

At fixed T and V, spontaneous change tends to reduce A. This makes Helmholtz free energy the natural potential for closed, rigid containers in contact with a heat reservoir, such as calorimetry cells and many solid‑state experiments.

4) Interpreting the sign of A

The absolute value of A depends on the chosen reference (zero) for energy and entropy. Negative values are common and not “wrong.” The physically meaningful quantity is often a difference, ΔA, between two states at the same temperature.

5) A worked numerical example

Suppose a sample has U = 5000 J, T = 300 K, and S = 10 J/K. Then T·S = 3000 J, so the calculator returns A = 2000 J. If the temperature rises to 350 K while S stays 10 J/K, then A = 1500 J, showing how higher temperature can lower available free energy for the same entropy.

6) Units and conversion checks

A common mistake is mixing “per mole” entropy with total internal energy. If you use molar entropy (J/mol·K), make sure U and A are also molar (J/mol). For quick sanity checks, note that 1 kJ = 1000 J, and 1 kcal ≈ 4184 J.

7) Practical applications

Helmholtz free energy is widely used for phase stability, lattice vibrations, and polymer elasticity. In statistical mechanics, an advanced link is A = −k·T·ln Z, where Z is the partition function and k is Boltzmann’s constant. This connects measured thermodynamics to microscopic models.

8) Tips and pitfalls

Ensure T is above 0 K, and avoid solving for T or S with a zero denominator. If your computed temperature becomes non‑physical, revisit signs, references, and whether your entropy basis matches your energy basis.

FAQs

1) Is Helmholtz free energy the same as Gibbs free energy?

They are different potentials. Helmholtz applies naturally at constant temperature and volume. Gibbs applies at constant temperature and pressure, using G = H − T·S.

2) Can A be negative?

Yes. The zero reference for energy and entropy is arbitrary, so absolute A can be negative. Differences, such as ΔA between states at the same temperature, carry the physical meaning.

3) What units should I use for entropy?

Use J/K (or compatible units). If you use molar entropy like J/mol·K, then internal energy and free energy should also be molar, such as J/mol, to keep the equation consistent.

4) Why must temperature be in Kelvin?

The formula uses absolute temperature. Celsius or Fahrenheit must be converted to Kelvin before multiplying by entropy. The calculator does this conversion automatically when you select the input unit.

5) What if my computed temperature is ≤ 0 K?

That result is non‑physical for ordinary equilibrium thermodynamics. It usually indicates inconsistent signs, mismatched unit basis (total vs molar), or an entropy value that should not be used for that state.

6) How accurate are the CSV and PDF exports?

The exports capture the exact inputs, selected units, and computed outputs shown on the page. They are ideal for lab notes, reports, and quick comparisons between scenarios.

7) When should I solve for entropy instead of A?

Solve for entropy when you have measured internal energy and free energy, and you know the temperature. This is helpful when comparing experimental data to models that predict free energy directly.

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Important Note: All the Calculators listed in this site are for educational purpose only and we do not guarentee the accuracy of results. Please do consult with other sources as well.