Enter Process Data
The page stays single-column overall. Inputs shift to 3 columns on large screens, 2 on tablets, and 1 on mobile.
Formula Used
1) Useful process heat
Quseful = m × Cp × ΔT × h × d
Where mass flow is in kg/h, heat capacity is in kJ/kg·K, temperature rise is in °C, hours are daily, and days are annual.
2) Total useful demand including losses
Qtotal = Quseful × (1 + loss%)
Standby and transfer losses cover heat leaking from lines, jackets, tanks, and idle periods.
3) Improved demand after heat recovery
Qimproved,net = Qimproved,total × (1 - recovery%)
Recovery reduces purchased energy by reusing heat from exhaust, condensate, or product streams.
4) Source energy
Source Energy = Q ÷ efficiency
Efficiency is entered as a percentage and converted to a decimal during the calculation.
5) Savings, cost, emissions, and payback
Energy Saved = Baseline − Improved
Cost Saved = Energy Saved × unit cost
CO₂e Saved = Energy Saved × emission factor
Payback = capital cost ÷ annual cost saved
How to Use This Calculator
- Enter a process name so the exported files stay identifiable.
- Select the energy source. Default cost and emission values will populate automatically.
- Add mass flow, specific heat capacity, and both temperature-rise cases.
- Enter baseline and improved thermal efficiencies.
- Include heat recovery and loss percentages for a more realistic chemistry scenario.
- Provide annual operating time, utility price, emissions factor, and optional project capital cost.
- Press Estimate Savings to show the result above the form.
- Use the CSV and PDF buttons to download the calculated summary.
Example Data Table
| Category | Parameter | Example Value | Unit |
|---|---|---|---|
| Input | Process name | Jacketed Reactor Heating | - |
| Input | Mass flow | 1,200 | kg/h |
| Input | Specific heat capacity | 3.80 | kJ/kg·K |
| Input | Baseline temperature rise | 65 | °C |
| Input | Improved temperature rise | 52 | °C |
| Input | Baseline efficiency | 74 | % |
| Input | Improved efficiency | 88 | % |
| Input | Heat recovery | 18 | % |
| Input | Baseline losses | 9 | % |
| Input | Improved losses | 4 | % |
| Input | Operating schedule | 16 × 300 | h/day × day/year |
| Input | Energy cost | 0.11 | per kWh-e |
| Input | Emission factor | 0.42 | kg CO₂e/kWh-e |
| Output | Baseline annual energy | 582,118.92 | kWh-e |
| Output | Improved annual energy | 306,387.78 | kWh-e |
| Output | Annual energy saved | 275,731.14 | kWh-e |
| Output | Annual cost saved | 30,330.43 | currency units |
| Output | Annual CO₂e saved | 115,807.08 | kg |
| Output | Simple payback | 0.59 | years |
FAQs
1) What does this calculator estimate?
It estimates annual source energy, cost, emissions, savings percentage, and payback for chemistry-related heating improvements. It compares a baseline process with an improved case using temperature, efficiency, losses, and recovery assumptions.
2) Why is specific heat capacity required?
Specific heat links mass and temperature change to thermal energy demand. In chemical processing, this is essential for solvents, slurries, water systems, and product streams heated or cooled during production.
3) Can this model heat recovery projects?
Yes. Enter the expected recovery percentage from condensate reuse, exchanger networks, exhaust capture, or warm product streams. The tool subtracts that recovered portion from purchased energy demand.
4) Which units should I use?
Use kg/h for mass flow, kJ/kg·K for specific heat, °C for temperature rise, kWh-equivalent for purchased energy, and your local currency for cost. Keep units consistent throughout.
5) Does it work for batch chemistry operations?
Yes, if you convert batch production into an average hourly mass flow over operating time. That gives a practical annualized estimate for reactors, tanks, dryers, and similar equipment.
6) Why could my savings become negative?
Negative savings mean the improved case uses more source energy than the baseline. This can happen when efficiency drops, losses increase, recovery is overstated, or the improved temperature rise is actually higher.
7) How should I choose the emission factor?
Use a local utility or site-specific factor whenever possible. The defaults are generic placeholders, useful for planning but less accurate than plant data, supplier data, or regional carbon accounting values.
8) What does simple payback mean here?
Simple payback divides project capital cost by annual cost savings. It shows how many years savings may need to recover the upfront spending, without discounting or escalation.