Input Parameters
Result
Example Data
| Units | Type | Bar | fy | f'c | Top | Epoxy | Spacing | Conf. | Class | Lightweight | Action |
|---|---|---|---|---|---|---|---|---|---|---|---|
| US | tension | #5 | 60000 | 4000 | no | no | good | normal | A | no | |
| US | tension | #8 | 60000 | 3000 | yes | yes | poor | normal | B | no | |
| SI | compression | #6 | 500 | 30 | no | no | good | excess | A | yes |
Formula Used (standards-inspired approximation)
This tool implements a simplified, standards-inspired method resembling common practice. It is intended for preliminary sizing and education. Always verify with governing codes, project specifications, and a licensed engineer.
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Tension development length
Approximate form:ld = (3 · ψt · ψe · ψs · fy) / (40 · λ · √f'c) · dbMinimum check: ld ≥ 12 in (305 mm).
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Lap splice length in tension
Ls,t = γclass · ldγclass = 1.0 (Class A) or 1.3 (Class B) in ACI preset.
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Compression lap splice (simplified)
Ls,c = max(0.0009 · fy · db / (λ · √f'c), m·db)m depends on preset (e.g., 21 for ACI; see preset notes).
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Factors
- ψt: 1.3 if top bar else 1.0 (ACI preset)
- ψe: 1.2/1.5 when epoxy, else 1.0 (ACI preset)
- ψs: 0.8 with excess transverse reinforcement else 1.0
- λ: 0.75 for lightweight concrete, else 1.0
How to Use
- Select the unit system, code preset, splice type, and bar size.
- Enter strengths and choose conditions; enable Auto Class if desired.
- Press Calculate to compute the required lap splice length.
- Review governing factors then export to CSV or PDF.
US Bar Schedule (Informational)
| Bar | Diameter (in) | Diameter (mm) | Area (in²) | Weight (lb/ft) | Action |
|---|---|---|---|---|---|
| #3 | 0.375 | 9.5 | 0.11 | 0.376 | |
| #4 | 0.500 | 12.7 | 0.20 | 0.668 | |
| #5 | 0.625 | 15.9 | 0.31 | 1.043 | |
| #6 | 0.750 | 19.1 | 0.44 | 1.502 | |
| #7 | 0.875 | 22.2 | 0.60 | 2.044 | |
| #8 | 1.000 | 25.4 | 0.79 | 2.670 | |
| #9 | 1.128 | 28.7 | 1.00 | 3.400 | |
| #10 | 1.270 | 32.3 | 1.27 | 4.303 | |
| #11 | 1.410 | 35.8 | 1.56 | 5.313 |