| Case | Ac (V) | Am (V) | m | fc | fm | Bandwidth | Status |
|---|---|---|---|---|---|---|---|
| Voice link | 10 | 6 | 0.6 | 1 MHz | 5 kHz | 10 kHz | Normal |
| Maximum clean | 8 | 8 | 1.0 | 500 kHz | 3 kHz | 6 kHz | 100% depth |
| Overdriven | 5 | 7 | 1.4 | 100 kHz | 2 kHz | 4 kHz | Overmodulation |
- m = Am / Ac (modulation index)
- s(t) = Ac[1 + m cos(2π fm t)] cos(2π fc t)
- Vmax = Ac(1+m), Vmin = Ac(1−m)
- AUSB = ALSB = (m Ac)/2 (each sideband amplitude)
- Bandwidth ≈ 2 fm
Optional power model (when a resistive load is provided): for a peak carrier voltage Ac across R, Pc = Ac2 / (2R) and Pt = Pc(1 + m2/2).
- Choose a mode, or keep Auto to infer a missing value.
- Enter Ac, plus either Am or m.
- Add fc and fm to see bandwidth and sidebands.
- Optionally enter load resistance to compute carrier and total power.
- Press Calculate. Results appear above the form under the header.
- Use Download CSV or Download PDF to save the results.
1) Modulation index and what it tells you
The modulation index m is the ratio of message amplitude to carrier amplitude: m = Am/Ac. A value of 0.25 means the envelope varies ±25% around the carrier level. Many voice links target 0.5 to 0.9 to keep distortion low while improving loudness at the receiver.
2) Envelope limits and distortion threshold
This calculator reports Vmax = Ac(1+m) and Vmin = Ac(1−m). When m > 1, the minimum becomes negative, meaning the envelope crosses zero and an envelope detector can clip or invert sections. The “100% modulation” point (m = 1.0) is the practical upper limit for clean AM.
3) Sidebands and their amplitudes
A single-tone message at fm produces two sidebands at fc ± fm. Each sideband’s peak voltage amplitude is (mAc)/2, so a 10 V carrier with m = 0.6 yields 3.0 V peak in the upper and 3.0 V peak in the lower sideband components.
4) Bandwidth planning with message frequency
For standard double-sideband AM, occupied bandwidth is approximately 2fm for the highest message frequency present. If your audio is limited to 5 kHz, plan about 10 kHz of RF bandwidth. If you widen audio to 10 kHz, bandwidth doubles to roughly 20 kHz, affecting channel spacing and filter design.
5) Power distribution across carrier and sidebands
If you enter a resistive load R, the tool estimates carrier power using Pc = Ac2/(2R) where Ac is peak carrier voltage across the load. Each sideband carries Pcm2/4, and total transmitted power is Pt = Pc(1 + m2/2). At m = 1, only one-third of power is in the sidebands.
6) Choosing levels for a clean measurement
For lab checks, start with a stable carrier amplitude and choose m between 0.2 and 0.8. Use a scope in “envelope view” to confirm the measured Vmax and Vmin match the computed values. If your generator reports RMS instead of peak, convert first to avoid power errors.
7) Practical example you can reproduce
Try Ac = 8 V, Am = 6 V, fc = 1 MHz, and fm = 5 kHz. The calculator gives m = 0.75, Vmax = 14 V, Vmin = 2 V, and bandwidth ≈ 10 kHz. With a 50 Ω load, Pc ≈ 0.64 W and Pt ≈ 0.82 W.
8) Quick troubleshooting checklist
If results look wrong, verify you used consistent units for fc and fm, and confirm Ac is not zero. Overmodulation warnings usually mean the audio level is too high relative to the carrier. Reduce Am or raise Ac until m returns to 1.0 or below.
Q1: What is a good modulation index for voice?
Many systems use 0.5–0.9. Lower values reduce noise improvement, while values near 1.0 maximize loudness without envelope distortion. Go above 1.0 only if you are not using simple envelope detection.
Q2: Why does AM bandwidth equal about 2fm?
A message at fm creates two sidebands at fc ± fm. The separation between the lowest and highest components is (fc+fm) − (fc−fm) = 2fm.
Q3: What does “overmodulation” mean here?
It means m > 1, so the envelope crosses zero. An envelope detector can then create severe distortion because the carrier “reverses” within the envelope, producing clipped audio at the output.
Q4: Are the amplitudes peak or RMS?
The calculator treats Ac and Am as peak amplitudes. If you have RMS values, convert first: Vpeak = √2 · VRMS for a sine wave. This matters for accurate power estimates.
Q5: Why is most AM power in the carrier?
The carrier is transmitted continuously even when the message is quiet. Sideband power scales with m2, so at moderate m values the carrier dominates. At m = 1, sidebands together carry one-half of Pc.
Q6: What frequencies appear for a single-tone message?
You get a carrier at fc, plus a lower sideband at fc − fm and an upper sideband at fc + fm. Their amplitudes are equal for standard AM.
Q7: How do I increase transmitted information power?
Increase m while keeping m ≤ 1, or use modulation schemes that reduce carrier power (like suppressed-carrier DSB or SSB). In classic AM, raising m boosts sideband power and improves received audio level.